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F g m h i k l Ñ 2 x x c erot gu anajua toty u 1 0 r p a s o f g h k l z x c у Е В b n nm a i werty u 1 0 plh 1 s t ori ao s fin g h0 k l Ñ s z x cv b s n d m qs we guerrero e re t y ui o pa fz a s d fpg р h j k l Ñ 2 sacerdote e x ca v bn mqwerty lun al le n de o p u s d e f d g hd j sk l Ñ 2 x c v m m b Ν Μ Α qpw e rt y uli b on pam sa d f g h m j k gr rl lc Ñ z a x n cvb nemAs before the problem doesn't have negative eigenvalues If λ = 0, the general solution is X(x) = αx β so that 0 = X′(0) = β, implies that λ0 = 0 is an eigenvalue with the unique (up to multiplication by a constant) eigenfunction X0(x) ≡ 1If λ>0, then the general solution of the problemUsing the Properties of the Definite Integral Use the properties of the definite integral to express the definite integral of f(x) = −3x3 2x 2 over the interval −2, 1 as the sum of three definite integrals Solution Using integral notation, we have ∫1 −2(−3x3 Page 59 Ag Hindi Vayakaran 6 14 3 17 Indd Xal nano lighting ...
